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3 years ago

What is the solution of the ineuality 1/2x+1/4 > 3/2x+3/4 ?

Mathematics

1 answer:

Tpy6a [65]3 years ago

5 0

Answer:

x < - $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{1}{2}$ x + $\frac{1}{4}$ > $\frac{3}{2}$ x + $\frac{3}{4}$

The lowest common multiple of 2 and 4 is 4

Multiply through by 4 to clear the fractions

2x + 1 > 6x + 3 ( subtract 2x from both sides )

1 > 4x + 3 ( subtract 3 from both sides )

- 2 > 4x ( divide both sides by 4 )

- $\frac{2}{4}$ > x

- $\frac{1}{2}$ > x , thus

x < - $\frac{1}{2}$

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Answer:

Mean: $\bar x = 40.61$

$Median =40.2$

$Mode = 43.4$

Step-by-step explanation:

Given

See attachment for data

Solving (a): The mean

Mean is calculated as:

$\bar x = \frac{\sum x}{n}$

From the attached:

$n = 14$

So, the mean is:

$\bar x = \frac{43.4+43.4+43.4+43.1+43.2+40.2+40.2+40.1+40.3+39.44+39.17+38.03+38.19+36.45}{14}$

$\bar x = \frac{568.58}{14}$

$\bar x = 40.61$

Solving (b): The median

$n = 14$ ; this is an even number. So, the median is:

$Median = \frac{1}{2}(n+1)$

$Median = \frac{1}{2}(14+1)$

$Median = \frac{1}{2}(15)$

$Median = 7.5th$

This implies that the median is the average of the 7th and 8th item.

Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>

The 7th and 8th items are: 40.2 and 40.2

The median is:

$Median = \frac{1}{2}(40.2 + 40.2)$

$Median = \frac{1}{2}*80.4$

$Median =40.2$

Solving (c): The mode

43.4 has the highest number of occurrence.

So:

$Mode = 43.4$

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