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3 years ago

What is the solution of the ineuality 1/2x+1/4 > 3/2x+3/4 ?

Mathematics

1 answer:

Tpy6a [65]3 years ago

5 0

Answer:

x < - $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{1}{2}$ x + $\frac{1}{4}$ > $\frac{3}{2}$ x + $\frac{3}{4}$

The lowest common multiple of 2 and 4 is 4

Multiply through by 4 to clear the fractions

2x + 1 > 6x + 3 ( subtract 2x from both sides )

1 > 4x + 3 ( subtract 3 from both sides )

- 2 > 4x ( divide both sides by 4 )

- $\frac{2}{4}$ > x

- $\frac{1}{2}$ > x , thus

x < - $\frac{1}{2}$

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zhenek [66]

10. Correct answer is C.
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3 years ago

2y-8+4y what is equal to this please help thanks

Nitella [24]

Answer:

$6y - 8$

$2(3y - 4)$

Step-by-step explanation:

The given expresion is 2y-8+4y.

We want to find an expression that is equal to 2y-8+4y.

We need to group like terms to obtain:

$2y + 4y - 8$

We can now combine the like terms to get:

$2y + 4y - 8$

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We can factor 2 to obtain:

$2(3y - 4)$

8 0

3 years ago

What is the value of k?

yawa3891 [41]

Answer:

Step-by-step explanation:

The vertex is (d, e)

for quadratic function: f(x) = ax² + bx + c we have:

d = -b/a and d = (x₁ + x₂)/2

a = 1, b = k, x₁ = -4, x₂=-2

so:

d = -b/a = -k/1 = -k and d = (x₁ + x₂)/2 = (-4-2)/2 = -3

-k = -3

k = 3

7 0

3 years ago

Solve the quadratic equation by using the quadratic formula. if the solution are not real, enter N/A 3x^2-7x+1=0

Vsevolod [243]

Answer:

$\displaystyle x=\frac{7\pm\sqrt{37}}{6}$

Step-by-step explanation:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(1)}}{2(3)}\\\\x=\frac{7\pm\sqrt{49-12}}{6}\\ \\x=\frac{7\pm\sqrt{37}}{6}$

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2 years ago

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

Art [367]

The area of sector is 1.57 m²

<u>Explanation:</u>

Given:

Radius, r = 3 m

Central angle of a sector = 1/9π radians

Area of sector, A = ?

We know:

Area of sector, A = $\frac{1}{2} r^2 \alpha$

where,

α is the central angle in radians

On substituting the value we get:

$A = \frac{1}{2} X(3)^2 X \frac{1}{9}X 3.14\\ \\A = 1.57 m^2$

Therefore, the area of sector is 1.57 m²

5 0

3 years ago