Question

A triangle is placed in a semi circle with a radius of 9 mm find the area of the shaded region of the semi circle (not including the triangle)

Answer 1

The area of the shaded region will be 46.17 ft.²The number of unit squares that cover the surface of a closed-form is the figure's area.

What is the area?

The space filled by a flat form or the surface of an item is known as the area.

The number of unit squares that cover the surface of a closed-form is the figure's area. Square centimeters and other similar units are used to measure area.

Given data;

Semicircle radius , r = 9 ft.

The height of the triangle, h=r=9 ft

The triangle is located where it is inscribed in the semicircle. The diameter of the semicircle is given as b, the base length of the triangle.

The diameter of the semicircle = 2 × The radius of the semicircle

D=2r

D= 2 × 9 ft

D= 18 ft.

Triangle base length,b = D= 18 ft.

The area of the triangle is found as;

$\rm A= \frac{1}{2}bh \\\\ A = \frac{1}{2} \times 18 ft. \times 9 ft. \\\\ A = 81 \ ft^2$

$A_{semi}={\rm \frac{A_{circle}}{2}} \\\\ A_{semi}= \frac{\pi \ r^2}{2}\\\\\ A_{semi}= \frac{3.14 \times 9^2}{2} \\\\ A_{semi} = 127.17 ft^2$

The area of the shaded region is;

a= 127.17 ft.² - 81 ft.²

a = 46.17 ft.²

Hence,the area of the shaded region will be 46.17 ft.²

To learn more about the area, refer to the link;

brainly.com/question/11952845

#SPJ1