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S_A_V [24]
3 years ago
15

What is the coefficient of x^2 y^3 in the expansion of (2x+y)^5

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

If it's x²y³ then we know it's the second term of the expansion, that known we can use the combination

C(5, 2) = 5!/(2!.3!) = 10

Then if we had something like

(a + b)^5 our second term would be 10a²b³ but as we can see it's "a²"

And in our case we have 2x as a

So we must do 2² too

2² = 4

10 . 4 = 40

Then our second term of the expansion would be

40x²y³

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Ksivusya [100]

h(x) = -2x2 + 12x - 3?

The axis of symmetry is :

x = 3

Hope this helps.

Welcome to Brainly!,

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PtichkaEL [24]

Step-by-step explanation:

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3 years ago
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almond37 [142]

Answer:

15?

Step-by-step explanation:

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Please help me with this
Zanzabum

Answer:

x=

−4y+32

9

Step-by-step explanation:

Let's solve for x.

y=

−9

4

x+8

Step 1: Flip the equation.

−9

4

x+8=y

Step 2: Add -8 to both sides.

−9

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x+8+−8=y+−8

−9

4

x=y−8

Step 3: Divide both sides by (-9)/4.

−9

4

x

−9

4

=

y−8

−9

4

x=

−4y+32

9

I think this is the right answer.

6 0
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