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denis23 [38]
3 years ago
11

Help ASAP!!

Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0
The answer is C. 
In t=2.33p, the constant is 2.33 and it stands for "<span>The tomatoes cost $2.33 per pound"</span>
QveST [7]3 years ago
7 0

Answer:

The answer is C. k  = 2.33; he tomatoes cost $2.33 per pound.

Step-by-step explanation:

In this case we have to determine the constant of proportionality of the equation. First we have to identify the variables:

Total charge or price = t

Pounds of tomatoes = p

So the constant of proportionality k is 2.33 because it determines how the total price of a certain number of tomato pounds change. FInally, to calculate the price per pound of tomatoes we have to use the equation a apply it using 1 pound of tomatoes:

t=2.33p\\t=2.33*(1)\\t=2.33

So the price of one pound is $2.33.

The answer is C. k  = 2.33; he tomatoes cost $2.33 per pound.

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Can someone please answer this question please answer it quickly I need it please answer it correctly and please please show wor
motikmotik

Answer:

The answer is B

Step-by-step explanation:

1. 2.50 x 2 is $5

2. 2.50 x 4 is $10

3. 2.50 x 3 is $7.50

4. 5 + 10 + 7.50 is 22.50 so you know the total should be 22.50.

5. It cant be A because 2.50 x 2 is 5 then timesing that by four would make 20 and then by 3 that would make $60 not $22.50

6. It is B because 2 + 4 + 3 is 9, 9x2.50 is 22.50

3 0
3 years ago
Read 2 more answers
Find the value of the x shown below.
WARRIOR [948]
It would be A. Because 2 squared + 10 squared = 104
7 0
2 years ago
2. In a certain school, there are 7 teachers for every 252 students. If there are 468 students, how many
Naddik [55]

Answer:

66.6

Step-by-step explanation:

If 7 teachers for 252 student

We divide 468÷7= 66.6

66.6 teacher

Here you are

3 0
3 years ago
Can someone help me pleaseeeee
Aleksandr-060686 [28]
The system is inconsistent because it has no solution. So the third option.

8 0
3 years ago
Choose all that are correct.
NeTakaya

Answer:

C

Step-by-step explanation:

7 0
3 years ago
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