Answer:
Option B. Range of the given sample data is 113.
Step-by-step explanation:
The given question is incomplete; here is the complete question.
Find the range for the given sample data.
The amounts below represent the last twelve transactions made to Juan's checking account. Positive numbers represent deposits and negative numbers represent debits from his
account.
$28 -$20 $67 -$22 -$15 $17 -$38 $41 $53 -$13 $30 $75
Option A. $75
Option B. $113
Option C. $37
Option D. -$113
Transaction done by Juan can be arrange from lowest to highest
-38 -22 -20 - 15 -13 17 28 30 41 53 67 75
Now we know rage of the sample data = Highest value - Lowest value
= 75 - (-38)
= 113
Therefore, range of the given sample data is 113.
Option B is the answer.
Answer:
hhsdhssmsxnxcjs
Step-by-step explanation:
You either need to add the two times together or you need to subtract them
Answer:
<u>So</u><u>,</u><u> </u><u>ADC</u><u> </u><u>=</u><u> </u><u>124</u><u>/</u><u>2</u><u> </u><u>=</u><u>></u><u> </u><u>⛰</u><u> </u><u>ADC</u><u> </u><u>=</u><u> </u><u>62</u><u>°</u>
Step-by-step explanation:
<u>If ABC i.e angle of centra = 124°</u>
<u>If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle </u>
- <u>If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle So, ADC = 124/2 => ⛰ ADC = 62°</u><u>.</u>
<em><u>Thank</u></em><em><u> </u></em><em><u>You</u></em><em><u> </u></em><em><u>☺️</u></em><em><u> </u></em><em><u>☺️</u></em><em><u>.</u></em><em><u> </u></em>
<h3>
<em><u>☆</u></em><em><u> </u></em><em><u>★</u></em><em><u> </u></em><em><u>Make It</u></em><em><u> </u></em><em><u>Brainlist Answer</u></em><em><u> </u></em><em><u>Please</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u> </u></em></h3>
Answer:
Impossible
Step-by-step explanation:
In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:
a = 5; b = -4; c = 3
The quadratic formula is 
(ignore the weird capital A)
Substitute a b and c:

Simplify:

Because
is the square root of a negative number, the answer would be imaginary.
Therefore, there are not solutions to this equation.
A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.
The graph never meets the x-axis. It looks like this: