Let x = number of months.
Let y = total number of fish in pond.
6% of 3,000 = 180 fish
We can use an equation to help us with this problem.
y = 3,000 + 180x - 400x. Combine like terms.
y = 3,000 - 220x. Plug 9 in for x.
y = 3,000 - 220(9). Solve for y
y = 1,020.
There are 1,020 fish in the pond after 9 months.
Answer:
4, 5, 6
Step-by-step explanation:
- 6m < -24
-m < -4
m > 4
m has to be greater than 4
18 is 10 players
19 is 94-70=24 the range is 24
Answer:
I did that before its A trust me
Step-by-step explanation:
Its annoying but wants yo learn it, itll get easy
