Answer:
y=-3x+14
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-4-26)/(6-(-4))
m=-30/(6+4)
m=-30/10
m=-3
y-y1=m(x-x1)
y-26=-3(x-(-4))
y-26=-3(x+4)
y=-3x-12+26
y=-3x+14
The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
<h3>How to factor the polynomial?</h3>
The expression is given as:
2x^2 + 4x + 3xy + 6y
Group the expression into two
[2x^2 + 4x] + [3xy + 6y]
Factor out each group
2x(x + 2) + 3y(x + 2)
Factor out x + 2
(2x + 3y)(x + 2)
Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)
Read more about factored expression at:
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Answer:
15-7=8
Step-by-step explanation:
you will have to use inverse operation
30, i don’t have the explanation i just remember this equation from Algebra 2 for some odd reason
