How can I solve this problem

What is the yintercept in the equation y=4x-3?

sergejj [24]

Answer:

-3

Step-by-step explanation:

The main formula for slope intercept form is y=mx+b

m=slope

b=y-intercept

3 0

3 years ago

Marcus looked out in the audience and saw 40% of the chairs were filled. There were 42 people sitting in the chairs. Enter the t

puteri [66]

Answer:

I say it is 16.8

Step-by-step explanation:

40 x 42

100

= 16.8

4 0

2 years ago

Nick, Paul and krutika share £80 in a ratio 1:1:2 how much money does each person get

Westkost [7]

Answer:

£20

Step-by-step explanation:

First you add 1 ,1 ,2 which =4

Next you divide 80 by 4 which give you the answer 20.

3 0

3 years ago

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

So

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago

Which postulate proves the two triangles congruent?

lorasvet [3.4K]

Answer:

B) SAS

Step-by-step explanation:

Notice that there are two pairs of congruent sides, AC is congruent with ZX, and BC is congruent with YZ. Since there's one angle in each triangle that's congruent to each other, we can say B is the only true answer.

3 0

3 years ago