4g = 24
First, divide both sides by 4. / Your problem should look like: g =
Second, simplify
to 6. / Your problem should look like: g = 6
Answer:
g = 6
Answer:
$ 60
Step-by-step explanation:
p(x) = 7x + 25
f(1) = 2.1² + 3 = 5
p(f(1)) = p(5) = 7 . 5 + 25 = 35 + 25 = 60
so he get $ 60 for 5 hours work with tips
Answer: this is only for the first question i think its the second one and the 3rd one i think
Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Answer:
Step-by-step explanation:
a) angle CAD= angle ODA ( in triangle OAD, OA=OD(same radius) angels opp to equal sides are equal)
hence angle CAD=42
b)angle b =90(angle subtended by diameter)
hence using angle sum property in triABC,
angle ACB=66-------------eq4
c) in tri OAD,
Angle AOD=180-(42+42)-------(using angle sum prop.)
=> 96-----------------eq1
angleACD=1/2 Angle AOD ( angle subtende by an arc at centre is double the angle subtended...)
hence angle ACD =1/2 x 96(from eq1)
angleACD=48--------------eq3
from eq 3,and eq4,
angle BCD= 48+66
=114 degree...
hope this helped you........pls mark brainliest
