In a game of rock paper scissors, what are the chances that someone playing against a person playing only paper would win?
As for the answer, if you were to make a chart to show rock, paper, and scissors, you'd be able to see that there's a 2/3 chance of winning by choosing rock. With scissors, there's also a 2/3 chance to win. Now with paper, there's only a 1/3 chance to win. Knowing that the other person will only play paper, the best answers would be to choose either rock or scissors.
(there are, of course, flaws with this concept, because the opponent could be lying about playing only paper. More or less, it's a good design to show probability.)
Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
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Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
Answer:
y = 7
Step-by-step explanation:
3y+9 = 2y+16, subtract 9 from both sides, 3y = 2y + 7, then subtract 2y from both sides, y = 7, and that's the answer
