Question

An advertiser claims that the average percentage of brown M&M'S candies in a package of milk chocolate M&M'S is 14%. Suppose you randomly select a package of milk chocolate M&M'S that contains 51 candies and determine the proportion of brown candies in the package.

Answer 1

Answer: The proportion of brown candies in the packages is 0.14.

Step-by-step explanation:

Since we have given that

Number of candies = 51 = n

Percentage of brown candies in a pack of milk chocolates = 14%

So, x = number of brown candies

$=\dfrac{14}{100}\times 51\\\\=0.14\times 51\\\\=7.14$

so, the proportion of brown candies in the package is given by

$\hat{p}=\dfrac{x}{n}=\dfrac{7.14}{51}=0.14$

Hence, the proportion of brown candies in the packages is 0.14.