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vagabundo [1.1K]
3 years ago
5

Hi can you help with some ratio and proportion questions​

Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

1a. 12 : 40

1b. 15 : 21

1c. 24 : 44

1d. 2 : 25

2. 40 boys and 100 girls

3. 96 girls

4. £71.43

5a. 9 : 4

5b. 3 : 1

5c. 3 : 5

6. 210 : 90

7. Sorry, I couldn't figure out how to solve this question :(

Step-by-step explanation:

Since I'll be using a similar method to solve these questions, I won't go into a detailed explanation for how I solved every single question. If you do need extra help, please ask in the comments below my answer.

1. Let's use part (a) as an example. The ratio is 3:10. To new ratio is ?:40. So, 10 becomes 40. What number multiplied by 10 equals 40? The answer is 4. If 10 is multiplied by 4, then 3 must be multiplied by 4 as well. 3*4 = 12, so the ratio is 12:40.

In part b the ratio is multiplied by 3, part c is 4, and part d is 1/2.

2. To solve this, add the values on both sides of the ratio together: 2 + 5 = 7. Now, divide the total number of pupils, 140, by 7: 140/7 = 20. Finally, multiply 20 by both sides of the ratio: 2 * 20:5 * 20 = 40:100. There are 40 boys and 100 girls.

3. To solve this I used the same method as the one I used in question 1.

4. The ratio is 5:140, where 140 becomes 2000. To solve, use the method used in question 1.

5. Simplifying ratios is the same as simplifying fractions. Find the greatest common factor of the values on both sides of the ratio and divide both sides by that factor. For example, in part a the factor for 45:20 is 5. 45/5 = 9 and 20/5 = 4. The ratio becomes 9:4.

For part b the factor is 9 and for part c the factor is 50.

6. Same method as was used in question 2.

Hope this helps :)

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Answer:

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Step-by-step explanation:

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Answer:

26.9 inches

Step-by-step explanation:

2x Pythagorean theorem

First we find the length of AC with ABC. AC is the hypotenuse of triangle ABC.

AC = sqrt(7^2+24^2) = sqrt625 = 25.

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8 0
3 years ago
Read 2 more answers
Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C
Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

A(5.3) = 0.5A(0)

We use this to find r. So

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{5.3}

(1-r)^{5.3} = 0.5

\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}

1 - r = 0.5^{\frac{1}{5.3}}

1 - r = 0.8774

So

A(t) = A(0)(0.8774)^{t}

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that A(26.5) = 14.5, and use this to find A(0). So

A(t) = A(0)(0.8774)^{t}

14.5 = A(0)(0.8774)^{26.5}

A(0) = \frac{14.5}{(0.8774)^{26.5}}

[tex]A(0) = 464[tex]

464 grams.

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Answer:

10.96

Step-by-step explanation:

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