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Natasha2012 [34]
3 years ago
7

What are the zeros of f(x) = x^2 + x - 20?

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0
X² + x - 20
= (x+5)(x-4)

x + 5 = 0
x = -5

x - 4 = 0
x = 4

hence the answer is C
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Suppose f is an exponential function and:
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Answer:  a) b= p(1 + r)^1 b) c= p(1 + r)^n c) d= p(1 + r)^m d) b^n=c

Step-by-step explanation:

Since f is an exponential function.

So, it is expressed as

f = p(1 + r)^

Here f is the present value

p is the initial value

r is the rate of growth per time period

t is the time period.

(a) b represents the 1-unit growth factor for f.

b= p(1 + r)^1

(b) c represents the n n-unit growth factor for f.

c= p(1 + r)^n

(c) d represents the m m-unit growth factor for f.

d= p(1 + r)^m

Write a formula that expresses c in terms of b.

Since

b=p(1+r)^1\\\\So,\\\\b=p(1+r)^{n\times \frac{1}{n}}\\\\b=(p(1+r)^n)^{\frac{1}{n}}\\\\b=c^{\frac{1}{n}}\\\\b^n=c

Hence, a) b= p(1 + r)^1 b) c= p(1 + r)^n c) d= p(1 + r)^m d) b^n=c

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