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3 years ago

7•2 + 7•23= pls help

Mathematics

2 answers:

katrin [286]3 years ago

8 0

Answer:

175

Step-by-step explanation:

if thats what you mean

S_A_V [24]3 years ago

3 0

Answer:

175

Step-by-step explanation:

7 times 2=14

7 times 23=161

161+14=175

hope this helps:)

plz can i get brainliest

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An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he

timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, $d_1 = 1\times610=610$ miles.

The distance covered at 310 degrees, $d_2 = 3\times610=1830$ miles.

Total distance covered, d, is the magnitude of the sum of vectors $\vec{d_1}$ and $\vec{d_2}$ as shown in the figure.

The angle between the vectors $\vec{d_1}$ and $\vec{d_2}$ , $\theta=310-270=40$ degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

$d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}$

$\Rightarrow d=2330.51$ miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B216%7D" id="TexFormula1" title="\sqrt{216}" alt="\sqrt{216}" align="absmiddle" class

muminat

Answer:

Step-by-step explanation:

4 0

2 years ago

Helppp plsssss!! Asap<br><br>Thanks

lubasha [3.4K]

Answer:

Ithink the answers B

Step-by-step explanation:

I think this because its even

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3 years ago

A house with an original value of increased in value to in years. What is the ratio of the increase in value to the original val

Anika [276]

Answer:

Ratio of the increase in value to the original value will be 1 : 5

Step-by-step explanation:

This question is incomplete; Here is the complete question.

A house with an original value to $150,000 increased in value to $180,000 in 5 years. what is the ratio of the increase in value to the original value of the house?

Original value of the house = $150000

Value of the house after 5 years = $180000

Appreciation in value of the house after 5 years = $180000 - $150000

= $30000

Now the ratio of the increase in value to the original value = $\frac{\text{Increased value}}{\text{Original value}}$

= $\frac{30000}{150000}$

= $\frac{1}{5}$ or 1 : 5

Therefore, ratio of the increase in value to the original value of the house is 1 : 5

6 0

3 years ago

How do I construct angle XYZ with a measure of 2 times the measure of angle ABC

Serjik [45]

I can’t understand why everyone complicates this question. It can be easily solved by similar triangles.

In this png, we have something to make sure.

∠B=∠DAB
∠
B
=
∠
D
A
B
(Yes, dab)

This also means AD=BD
A
D
=
B
D
.

This is our basic construction of D, which is going to help us.

∠ADC=∠DAB+∠B=2∠B=∠CAB
∠
A
D
C
=
∠
D
A
B
+
∠
B
=
2
∠
B
=
∠
C
A
B

∠CAD=∠CAB−∠DAB=∠B
∠
C
A
D
=
∠
C
A
B
−
∠
D
A
B
=
∠
B

These are based on the fact that ∠A=2×∠B
∠
A
=
2
×
∠
B

Actually these conditions suffice. Because I am just proving that △ACD∼△BCA
△
A
C
D
∼
△
B
C
A

Similarity makes us realize the following:

ACBC=ADAB
A
C
B
C
=
A
D
A
B

and

ACBC=CDAC
A
C
B
C
=
C
D
A
C

So

AC×AB=BC×AD
A
C
×
A
B
=
B
C
×
A
D

and

AC2=BC×CD
A
C
2
=
B
C
×
C
D

So

BC2=BC×(BD+CD)=BC×(AD+CD)
B
C
2
=
B
C
×
(
B
D
+
C
D
)
=
B
C
×
(
A
D
+
C
D
)

=AC×AB+AC2
=
A
C
×
A
B
+
A
C
2

Q.E.D.
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3 years ago