<h2>Given :-</h2>
- Volume of Tank is 396 m³
- Length of Tank is 7.2 m and breadth is 5.5 m
<h2>To Find :-</h2>
<h2>Solution :-</h2>
<h2>Using Formula :-</h2>
- Volume of Cuboid = L × b × h
<h2>Putting Values :-</h2>
<h3>So, The Height/Depth of Tank is </h3><h3>10 m</h3>
Answer:
7 and 8
Step-by-step explanation:
![{x}^{2} + 7x + 12](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%207x%20%2B%2012)
(x+3)(x+4)
![{x}^{2} + 8x + 12](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20%2B%2012)
(x+2)(x+6)
Answer:
ounces of clay are left in the bucket.
Step-by-step explanation:
We have been given that Luis and Glen share a 16-ounce bucket of clay. By the end of the week, Luis has used 5/8 of the bucket, and Glen has used 1/4 of the bucket of clay.
To solve our given problem, we need to subtract sum of clay used by Luis and Glen from total amount of clay.
![16-(\frac{5}{8}+\frac{1}{4})](https://tex.z-dn.net/?f=16-%28%5Cfrac%7B5%7D%7B8%7D%2B%5Cfrac%7B1%7D%7B4%7D%29)
Now, we will make a common denominator as:
![\frac{16\cdot 8}{8}-(\frac{5}{8}+\frac{1\cdot 2}{4\cdot 2})](https://tex.z-dn.net/?f=%5Cfrac%7B16%5Ccdot%208%7D%7B8%7D-%28%5Cfrac%7B5%7D%7B8%7D%2B%5Cfrac%7B1%5Ccdot%202%7D%7B4%5Ccdot%202%7D%29)
![\frac{128}{8}-(\frac{5}{8}+\frac{2}{8})](https://tex.z-dn.net/?f=%5Cfrac%7B128%7D%7B8%7D-%28%5Cfrac%7B5%7D%7B8%7D%2B%5Cfrac%7B2%7D%7B8%7D%29)
![\frac{128}{8}-(\frac{5+2}{8})](https://tex.z-dn.net/?f=%5Cfrac%7B128%7D%7B8%7D-%28%5Cfrac%7B5%2B2%7D%7B8%7D%29)
![\frac{128}{8}-\frac{7}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B128%7D%7B8%7D-%5Cfrac%7B7%7D%7B8%7D)
![\frac{128-7}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B128-7%7D%7B8%7D)
![\frac{121}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B121%7D%7B8%7D)
![15\frac{1}{8}](https://tex.z-dn.net/?f=15%5Cfrac%7B1%7D%7B8%7D)
Therefore,
ounces of clay are left in the bucket.
Answer:
54. slope: -1/5 y-intercept: -6
55. slope: -3x y-intercept: 12
Step-by-step explanation: