Answer:
the hot air balloon is hotter than me
Step-by-step explanation:
First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
I think you have to solve like each section like (5x3+3)2 first solve that and then solve the middle one and then the last one and I think they all have to be equal to each other , and if they aren’t then her anwser isn’t correct
Yeah it would be A. because x approaching infinity is to the right of the graph, and since there is a horizontal asymptote at -3 then its correct
Answer:
a. -5/2
Step-by-step explanation:
