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3 years ago

What is the percent of change in 6 yards to 36 yards

Mathematics

2 answers:

BaLLatris [955]3 years ago

3 0

Answer:

The percent of change in 6 yards to 36 yards is 500% .

Step-by-step explanation:

Formula

$Percentage = \frac{Change\ in\ value\times 100}{initial\ value}$

Where

Change in value = Final value - initial value

As given

The percent of change in 6 yards to 36 yards.

Final value = 36 yards

initial value = 6 yards

Change in value = 36 - 6

= 30 yards

Put in the formula

$Percentage = \frac{30\times 100}{6}$

$Percentage = \frac{3000}{6}$

Percentage = 500%

Therefore the percent of change in 6 yards to 36 yards is 500% .

Paul [167]3 years ago

3 0

This is equal to the amount of change over the original amount
In this case the amount of change is 30 (36-6=30)

$\frac{30}{6}$ = 5
And 5 = 500% percent of change

Note that this is different than: What percent of 6 is 36? That would be 600% $\frac{36}{6}$

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What is the sum of the first 37 terms of the arithmetic sequence?

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Answer:

The sum of the first 37 terms of the arithmetic sequence is 2997.

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

$a_{n} = a_{1} + (n-1)*d$

The sum of the first n terms of an arithmetic sequence is given by:

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In this question:

$a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6$

We want the sum of the first 37 terms, so we have to find $a_{37}$

$a_{n} = a_{1} + (n-1)*d$

$a_{37} = a_{1} + (36)*d$

$a_{37} = -27 + 36*6$

$a_{37} = 189$

Then

$S_{37} = \frac{37(-27 + 189)}{2} = 2997$

The sum of the first 37 terms of the arithmetic sequence is 2997.

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