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3 years ago

How do you solve for x when given |x+a| =b

Mathematics

1 answer:

umka21 [38]3 years ago

5 0

It should be B-a since that is how you would find x+4=9 9-4=5

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Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

3 years ago

Find the points which defined the reflection of the figure giving by A(2,2) B (3,7) C (5,5) reflected across the X-axis

elixir [45]

well the formula to reflecting across the x-axis is (x,-y).so the final points are A'(2,-2) B'(3,-7) C(5,-5) ANSWER

additional information

By the way the -y in the formula does not mean every number will always be negative it means switch the sign so if the point is (5,-7) than reflecting across the x-axis it would be (5,7)

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juin [17]

Answer:

123445

Step-by-step explanation:

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The first choice, 5+7n.

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