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Tanzania [10]
3 years ago
14

Of the following equations below, which equation represents a direct variation between x and y?

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

C. y +3 = x +3

Step-by-step explanation:

We need to find in below option x has direct variation with y.

We solve for each;

A. 2y = 3x-7

From above equation we can state that 2 times y is equal to 7 less than 3 times of x.

Hence it doesn't represent direct variation.  

B. y-4 = x+6

Solving above expression we get;

y-4 = x+6\\y = x+6+4\\y=x+10

From above equation we can state that y is equal to 10 more than x.

Hence it doesn't represent direct variation.

C. y+3 = x+3

Solving above expression we get;

y+3 = x+3\\y = x+3-3\\y=x

From above equation we can state that y is equal to x.

Hence it represent direct variation.

D. 4y+1 = 4x-1

Solving above expression we get;

4y+1 = 4x-1\\4y = 4x-1-1\\4y=4x-2

From above equation we can state that 4 times y is equal to 2 less than 4 times of x.

Hence it doesn't represent direct variation.

Hence the Answer which represent direct variation of x and y is,

C. y+3 = x+3

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A bakery uses 10 3/5 ounces of icing for every 1/4 of a cake. What is the unit rate in ounces of icing per cake?
natita [175]

Answer:

42\frac{2}{5}}\frac{ounces}{cake}

Step-by-step explanation:

we know that

To calculate the unit rate divide the total ounces by 1/4 of a cake

but first convert mixed number to an improper fraction

10\frac{3}{5}\ ounces=\frac{10*5+3}{5}=\frac{53}{5}\ ounces

\frac{(53/5)}{(1/4)}=\frac{53*4}{5}=\frac{212}{5}\frac{ounces}{cake}

Convert to mixed number

\frac{212}{5}\frac{ounces}{cake}=\frac{210}{5}+\frac{2}{5}=42\frac{2}{5}}\frac{ounces}{cake}

5 0
4 years ago
What is x pls and than you
Sunny_sXe [5.5K]

Answer:

2

Step-by-step explanation:

5x - 10 = 0

    +10    +10

5x = 10

/5     /5

x = 2

3 0
3 years ago
Read 2 more answers
What is the result of subtracting the polynomial (X2 + 3x) from the<br> polynomial (-2X + 4X2 +5)?
HACTEHA [7]

Answer: -5x+3x²+5

Step-by-step explanation:

 (-2x+4x²+5)-(x²+3x)

=-2x+4x²+5-x²-3x

=-2x-3x+4x²-x²+5

=-5x+3x²+5

=3x²-5x+5 (if you are required to write in standard form)

4 0
3 years ago
Boat A is 20 km from port on a bearing of 025° and boat B is 25 km from port on a bearing of 070°. Boat B is in distress. What b
tiny-mole [99]

Answer: Boat A should travel 152.8° to reach B

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo. Triangle ABP is formed. A represents the position of boat A. B represents the position of boat B. P represents the position of the port.

We would determine AB by applying the law of cosines

AB² = AP² + BP² - 2AP×BPCosP

AB² = 20² + 25² - 2 × 20 × 25 × Cos45

AB² = 1025 - 707.10678 = 317.89322

AB = √317.89322 = 17.83

We would determine the bearing of B from A by finding angle A. We would apply the sine rule.

AB/SinP = AP/Sin A

17.83/Sin45 = 20/SinA

Cross multiplying, it becomes

17.83 × SinA = 20Sin45 = 14.14

SinA = 14.14/17.83 = 0.79

A = Sin^-1(0.79) = 52.2°

The total angle at A is 65 + 52.2 = 117.2°

The angle formed outside the third quadrant is 117.2 - 90 = 27.2°

Therefore, bearing B from A is

180 - 27/2 = 152.8°

3 0
3 years ago
When twice a number is increased by 10, the sum is 42.what is the number?
JulsSmile [24]
22, hope this helps! :))
3 0
3 years ago
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