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melamori03 [73]
3 years ago
13

What is the result of converting 24,000 grams into kilograms

Mathematics
2 answers:
Westkost [7]3 years ago
5 0
24000 grams is 24 kilograms
Alenkasestr [34]3 years ago
4 0
The result is 24. Hope this helps.
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Kinda low, you would need luck to be on your side!
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Convert 46,500 scientific notation
Shkiper50 [21]
46500....ok...pay attention....put a decimal behind the first number  4.6500  ....now start counting all the numbers to the right of the decimal...there are 4 numbers.....so ur answer is 4.65 x 10^4
8 0
3 years ago
Solve for the variable
liraira [26]

Answer:

y = 25

Step-by-step explanation:

30=\frac{6}{5} y\\\\\frac{6}{5} y=30\\\\(\frac{6}{5} y)5=30*5\\\\6y=150\\\\\frac{6y=150}{6}\\\\\boxed{y=25}

Hope this helps!

8 0
3 years ago
The area of a rectangle is expressed as (14r + 21) square feet. If the width of the
lilavasa [31]

Answer:

 L  = 2r  + 3

Step-by-step explanation:

Given parameters:

Area of rectangle  = 14r + 21

Width of the rectangle  = 7ft

Unknown:

Length of the rectangle  = ?

Solution:

If the length of the rectangle is designated as L;

 Area of a rectangle = Length x width

Now insert the parameters:

           14r + 21   = L x 7

            L  = \frac{14r + 21}{7}  

           L  = 2r  + 3

8 0
3 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
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