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3 years ago

How do you identify quadratic equations?

1 answer:

8 0

Often the easiest method of solving a quadratic equation is by factoring. Factoring means finding expressions that can be multiplied together to give the expression on one side of the equation. ... The equation x2+x−6=0 x 2 + x − 6 = 0 is in standard form.

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21) Jaquan earns $5 per hour raking leaves. He needs at least $170 to buy a new deo game system. Write an inequality that descri

Anna007 [38]

5x>/170
(WORK SHOWN BELOW)

5 0

3 years ago

SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

$C=180-(A+B)$

$C=180-(21.24+27.14)$

$C=131.62$

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

$b^2=a^2+c^2$

$4^2=2^2+c^2$

$16=4+c^2$

$12=c^2$

$c=\sqrt{12}$

$c=2\sqrt{3}$

- We can find angle C using the cosine trig identity

$cos(C)=\frac{adjacent}{hypotenuse}$

$cos(C)=\frac{2}{4}$

$C=arccos(\frac{2}{4} )$

$C=60$

- Now we can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+60)$

$A=30$

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+34.88)$

$A=55.12$

- We can find side a using the tangent trig identity

$tan(C)=\frac{opposite-side}{adjacent-side}$

$tan(34.88)=\frac{7}{a}$

$a=\frac{7}{tan(34.88)}$

$a=10.04$

- Now we can find side b using the Pythagorean theorem

$b^2=a^2+c^2$

$b^2=10.04^2+7^2$

$b^2=149.8$

$b=\sqrt{149.8}$

5 0

3 years ago

The value of x = 60° 5 x 30°

nikklg [1K]

Answer:

Step-by-step explanation:

with reference angle 30°

perpendicular (p) = 5

hypotenuse (h) = x

Now

sin 30° = p / h

1 / 2 = 5 / x

x = 10

Hope it will help :)

6 0

3 years ago

The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i

melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

3 0

3 years ago

Graph y=-5x+4 please help, I have an iReady to do.

Anna007 [38]

Answer:

(look at graph below)

Step-by-step explanation:

5 0

2 years ago