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Semmy [17]
2 years ago
12

Tim is an elementary school art teacher. His students are sculpting a replica of a shark out of clay. Tim has given them one blo

ck of clay to make 20 conical shark teeth for the sculpture. The block contains 81 cm3 of clay. If each tooth is solid and has a 2.5 cm base diameter, what is the maximum height each tooth can be? Assume that the students use all the clay.
Mathematics
2 answers:
Darina [25.2K]2 years ago
8 0
Radius = 1.25cm
81cm3 / 20 = 4.05 cm3 per cone
V cone = πr^2 (h/3)
So then 4.05 = π(1.25)^2 (h/3)
Then h/3 = .825 and then

h = 2.475 cm
labwork [276]2 years ago
8 0

Answer: 2.47cm

Step-by-step explanation:    BOOM!

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Can somebody tell me the answer of the question: if a human can eat 5% more than a animal how much can it a animal ??
GenaCL600 [577]

Answer:

Step-by-step explanation:

If human can eat 5% more than animal then the animal eats 5 % less than human so the answer is 5% less than human

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6 0
3 years ago
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Parenthesis first
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3 years ago
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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
T+2/3t-1/3 I really need this question to be answered
Murrr4er [49]

<u> Equation:</u>

x(x      -     5)     +     3(x     +     5)

<u>Steps:</u>

x(x      -     5)     +     3(x     +     5)

<u>Expand:</u>

x(x     -     5 ):           x^2      -    5x

x^2    -    5x     +   3(x      +     5)

<u>Expand:</u>

3(x     +    5):        3x   +    15

x^2     -     5x     +     3x       +     15

<u>Add Similar Elements:   </u>  

-5x      +    3x    

=         -2x

Answer        x^2    -     2x      +    15    Doesn't Factor






Hope that helps!!!                                  : )


         


5 0
3 years ago
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