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3 years ago

Plz help plz plz plz plz

Mathematics

1 answer:

Likurg_2 [28]3 years ago

3 0

Answer:

Step-by-step explanation:

The ratio of green : pink = 32 : 56 = 4 : 7

After 7 pink are given away, then

ratio = ? : 49 = 4 : 7 ← ratio has to be the same

Using proportion

$\frac{?}{4}$ = $\frac{49}{7}$ ( cross- multiply )

7? = 196 ( divide both sides by 7 )

? = 28

Thus the ratio = 28 : 49 = 4 : 7

Thus 32 - 28 = 4 green should be given

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Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

the cost c in dollars for the care and maintenance of a horse and carriage is c= 15x+2000, where x is the number of rides. they

olga nikolaevna [1]

Cost = 15x + 2000
Earning = 35x

At break even, cost = earning

35x = 15x + 2000
20x = 2000
x = 100

100 rides are needed to break even.

8 0

3 years ago

Determine the intercepts of the line. y-6=4(x+5)

Westkost [7]

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (−13/2,0)(-132,0)

y-intercept: (0,26)

7 0

3 years ago

Read 2 more answers

(-1/8c+16)-(3/8+3c) difference

zloy xaker [14]

Answer:

-25 (c-5) / 8

Negative 25 (c-5) over 8

5 0

3 years ago

Read 2 more answers

Triangle ABC below is reflected across the y-axis and then translated 1 unit right and 2 units down.

hodyreva [135]

Any point with coordinates (x, y) reflected across the y-axis is going to have the opposite x value that it did before.
You should be able to find the coordinates yourself for part a. (you didn't provide the original ones so I can't help you there)
Here is the "rule" for a reflection across the y-axis:
$(x,\ y)\rightarrow(-x,\ y)$
And when we go 1 unit to the right and 2 down, that's the same as
$(x,\ y)\rightarrow(x+1,\ y-2)$

Combining those into one rule is pretty simple, Use our result for the first in the second and we would get $(-x+1,\ y-2)$ , so the rule is
$\boxed{(x,\ y)\rightarrow(-x+1,\ y-2)$ .
Part A is asking for the coordinates after the reflection (x, y) ⇒ (-x, y).
Part C is asking for the coordinates after the full translation ⇒ (-x+1, y-2)

8 0

3 years ago