Answer:
1 hundreths is 10 times greater than 1 thousandths.
Step-by-step explanation:
just like 100 is ten times greater than 10.
Answer:
5
Step-by-step explanation:
![f(x) = 2x + 5 \\ pluggng \: x = 0 \\ f(0) = 2 \times 0 + 5 = 0 + 5 = 5 \\ f(0) =5 \\](https://tex.z-dn.net/?f=f%28x%29%20%3D%202x%20%2B%205%20%5C%5C%20pluggng%20%5C%3A%20x%20%3D%200%20%5C%5C%20f%280%29%20%3D%202%20%5Ctimes%200%20%2B%205%20%3D%200%20%2B%205%20%3D%205%20%5C%5C%20f%280%29%20%3D5%20%5C%5C%20)
Hello from MrBillDoesMath!
Answer: f(x) = (2/3)*x -3 -- which is not a provided answer..
Discussion:
We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:
y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3
= (2/3)*x + 4
Subtract 7 from both sides:
y + 7 - 7 = (2/3)*x + 4 - 7
or
y = (2/3)*x -3
Thank you,
MrB
y + 7= 2/3(x+6)
We have been given the function ![y=e^{4x}](https://tex.z-dn.net/?f=y%3De%5E%7B4x%7D)
We know that the range is set of y values for which the function is defined. Therefore, we will find the value for x and then observe the restriction is y's values.
![y=e^{4x}\\\ln y = \ln (e^{4x})\\\ln y =4x\\x=\frac{1}{4}\ln y](https://tex.z-dn.net/?f=y%3De%5E%7B4x%7D%5C%5C%5Cln%20y%20%3D%20%5Cln%20%28e%5E%7B4x%7D%29%5C%5C%5Cln%20y%20%3D4x%5C%5Cx%3D%5Cfrac%7B1%7D%7B4%7D%5Cln%20y)
Now, we know that logarithm function is not defined for negative values. Hence, the value for y is always greater than zero.
Therefore, the range of the function is given by y>0
B is the correct option.
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