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IgorLugansk [536]
3 years ago
14

Find the volume of a solid

Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0
So, to solve this we have a Circular cylinder and half a Sphere.

Total Volume 402+134 = 536 ft³  <- Answer

Calclulations
Answer:

r = 4 in
h = 8 in
V = 402.124 in³
L = 201.062 in²
T = 50.2655 in²
B = 50.2655 in²
A = 301.593 in2
Agenda 
r = radius
h = height
V = volume
L = lateral surface area
T = top surface area 
B = base surface area 
A = total surface area
π = pi = 3.14159
<span>√ = square root
</span>
Formula cylinder:V = πr²h
The answer for the sphere

r = 4 ft
V = 268 ft/2=134 ft³
A = 201 ft²
C = 25.1 ft

Agenda
r = radius
V = volume
A = surface area
C = circumference
π<span> = pi = 3.14159</span>
<span>√ = square root</span>

Formula:

Volume of a sphere:V = (4/3)πr³
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Oliver has music lessons in Monday Wednesday and Friday.Each lesson is 3/4 of an hour Oliver says he will have lessons for three
Hoochie [10]
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4 0
3 years ago
A tiling company completes two jobs. The first job has $1200 in labor expenses for 40 hours worked, while the second job has $15
daser333 [38]

Answer:

The correct option is;

1560 = 30(52) + b

Step-by-step explanation:

The cost of the first job = $1,200 in labor and expenses

The number of hours worked in the first job = 40

The second job costs $1,560 in labor and expenses

The number of hours worked in the second job = 52

If the cost of labor per hour = L and the expenses = b, we have;

$1,200 = 40×L + b......................(1)

$1,560 = 52×L + b.......................(2)

Subtracting equation (1) from (2), we have;

52×L + b - (40×L + b) =  52×L - 40×L + b - b = $1,560 - $1,200 = $360

12×L = $360

L = $360/12 = $30/hour

From equation (1), we have;

$1,200 = 40×L + X =  40×$30 + b

Therefore, the equation that can be used to calculate the y-intercept of the linear equation is either;

1200 = 40(30) + X or 1560 = 32(52) + b, which gives the correct option as 1560 = 32(52) + b

6 0
3 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
4 years ago
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