Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
So first put this in slope intercept form, y=mx+b. subtract x from both sides so now you have 3y=-x+3 and to get y by itself divide both sides by 3 so now you have y=(-x/3) +1 or y=-1/3(x)+1 the slope is m and the y-intercept is b so the slope is -1/3 and the y-intercept is 1
Answer:
a) 47
b) 3
c) 1
d) 2
e) 47
f) 3
Step-by-step explanation:
read the textbook
Answer:
B) You conclude that the mean height of all Quarter Horses is close to 15.2 hands
Step-by-step explanation: