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Maksim231197 [3]

3 years ago

15

your basketball team scored 4 fewer than twice as many points as the other team.write an expression for the number of points you

r team scored.

2 answers:

Anna35 [415]3 years ago

8 0

2X-4, X being the other teams score then times 2 minus 4

Jobisdone [24]3 years ago

3 0

You=x
Other team=y

Y•2-4

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The intersection of a 3-dimensional solid with a plane

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Answer:

a cross-section

Step-by-step explanation:

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3 years ago

List the imaginary value of the number 3+2i.

ki77a [65]

Hello from MrBillDoesMath!

Answer:

The imaginary part = 2i.

Discussion:

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3 years ago

Simplify by rationalizing the denominator.<br> 15√2 / √270

ladessa [460]

$\frac{ \sqrt{15} }{3}$ ✅

Step-by-step explanation:

$\frac{15 \sqrt{2} }{ \sqrt{270} } \\ \\ = \frac{15 \sqrt{2} }{ \sqrt{270} } \times \frac{ \sqrt{270} }{ \sqrt{270} } \\ \\= \frac{15 \sqrt{2} \times \sqrt{270} }{270} \\\\ (∵ \sqrt{a} \times \sqrt{a} = a) \\\\ = \frac{15 \sqrt{540} }{270} \\ \\= \frac{ \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 5} }{18} \\ \\ = \frac{ \sqrt{ {2}^{2} \times {3}^{2} \times 15 } }{18} \\ = \frac{2 \times 3 \sqrt{15} }{18} \\ \\ = \frac{6 \sqrt{15} }{18} \\ \\ = \frac{ \sqrt{15} }{3}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}$

7 0

3 years ago

Read 2 more answers

Are the pair of lines parallel, perpendicular or neither? 8x-4y=12 and 4x-y=-15

Orlov [11]

Answer:

neither, would technically be intersecting lines tho

Step-by-step explanation:

6 0

3 years ago

A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the p

andreyandreev [35.5K]

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that $\mu = 0.55$

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577$

$P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894$

5 0

4 years ago