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marusya05 [52]
3 years ago
8

Which of the following best describes a chord?

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer:

Option A: A chord is a line segment that has both endpoints on a circle.

Step-by-step explanation:

A chord of a circle is a line segment whose endpoints both lie on the circle.

In general a chord is a line segment that connects two distinct points on a circle. Its also called a secant in a circle, that intersects the circle at exactly two points.

Here, option A is correct.

Alinara [238K]3 years ago
5 0

Answer:

The Answer is A, a line segment that has both endpoints on a circle.

Step-by-step explanation:

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What is the equation in vertex form of the quadratic function with a vertex at (-1, -4) that goes through (1, 8)?
cestrela7 [59]

Answer:

y = 3(x+1)^2 - 4

Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:

y - k = a(x-h)^2, or

y      = a(x-h)^2 - k

Substituting the coefficients of the vertex (-1, -4), we get:

y      = a(x + 1)^2 - 4

Substituting the coordinates of the given point, (1,8), we get:

8      = a(1+1)^2 - 4, which simplifies to:

8      = a(2)^2 - 4, or

8  = 4a - 4.  Then 4a = 12, and a = 3.

Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).


5 0
3 years ago
What is 4/20 as a percent? And how do I find it?
Reika [66]
Well u know 4/20 equals 0.2 as a decimal but as a percentage it is 20% so 4/20 as a percentage is 20%
4 0
3 years ago
Which of the following ordered pairs is a solution to y=2^x
Masja [62]
What are the choices?
7 0
3 years ago
Simplify the following: 6i^3 +4j^2 -6i<br> Please show work
Vadim26 [7]

Answer:

Concept: Vectors

  1. I think the confusion here might be the usage of i and j
  2. Just to let you know, i=x and j=y
  3. So let's use that fact to conceptualize this
  4. 6x^3+4y^2-6x
  5. We can simplify by applying a common factor
  6. 2(x^3+2y^2-3x)
  7. Thats the most we can simplify this
6 0
2 years ago
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
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