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2 years ago

13

A couple plans to have 4 children. Assuming that boys and girls are equally likely, find the probability that the couple will ha

ve at least one boy?

1 answer:

iVinArrow [24]2 years ago

3 0

$A$ - the couple will have at least one boy

$A'$ - the couple will have only girls

$P(A)=1-P(A')$

$|\Omega|=2^4=16\\|A'|=1\\\\P(A')=\dfrac{1}{16}\\\\P(A)=1-\dfrac{1}{16}=\dfrac{15}{16}$

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Solve this quadratic equation using the quadratic formula. 2x 2 - 10x + 7 = 0

sladkih [1.3K]

Answer:X=11/10

Step-by-step explanation:

2x2-10x+7=0

<u><em>4</em></u>-10x+<u><em>7</em></u>=0

11-10x=0

-10x= -11

Divide both side by -10

-10x/-10. -11/-10

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3 years ago

Read 2 more answers

What is the number 5 2/7 written as a improper fraction

WARRIOR [948]

Answer:

the answer is 37/7

Step-by-step explanation:

u multiply the 5 and the seven and add the 2 and u get 37/7 so u keep the denominator the same

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3 years ago

I can’t figure this out

patriot [66]

Answer:

$m \leq 4.3$

Step-by-step explanation:

We need to get m on one side all by itself. To achieve this, let's subtract both sides by 1.2 to get $m \leq 5.5-1.2 \implies m \leq 4.3$ .

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3 years ago

The 2010 General Social Survey reported a sample where about 48% of US residents thought marijuana should be made legal. If we w

Sati [7]

Answer:

The sample size is $n = 600$

Step-by-step explanation:

From the question we are told that

The sample proportion is $\r p = 0.48$

The margin of error is $MOE = 0.04$

Given that the confidence level is 95% the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the values is

$Z_{\frac{\alpha }{2} } = 1.96$

The reason we are obtaining critical value of $\frac{\alpha }{2}$ instead of $\alpha$ is because

$\alpha$ represents the area under the normal curve where the confidence level interval ( $1-\alpha$ ) did not cover which include both the left and right tail while

$\frac{\alpha }{2}$ is just the area of one tail which what we required to calculate the margin of error

Generally the margin of error is mathematically represented as

$MOE = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p(1- \r p )}{n} }$

substituting values

$0.04= 1.96* \sqrt{ \frac{0.48(1- 0.48 )}{n} }$

$0.02041 = \sqrt{ \frac{0.48(52 )}{n} }$

$0.02041 = \sqrt{ \frac{ 0.2496}{n} }$

$0.02041^2 = \frac{ 0.2496}{n}$

$0.0004166 = \frac{ 0.2496}{n}$

=> $n = 600$

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3 years ago

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Answer:

....................

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3 years ago