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Stella [2.4K]
2 years ago
13

A couple plans to have 4 children. Assuming that boys and girls are equally likely, find the probability that the couple will ha

ve at least one boy?
Mathematics
1 answer:
iVinArrow [24]2 years ago
3 0

A - the couple will have at least one boy

A' - the couple will have only girls

P(A)=1-P(A')

|\Omega|=2^4=16\\|A'|=1\\\\P(A')=\dfrac{1}{16}\\\\P(A)=1-\dfrac{1}{16}=\dfrac{15}{16}

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Julli [10]
Due to the conditions, my answer would be 100.
3 0
3 years ago
In the game of roulette, a player can place a $4 bet on the number 10 and have a 1/38 probability of winning. If the metal ball
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5 0
3 years ago
The math says expand 5(2-7x) what is the answer
kow [346]

Step-by-step explanation:

in my opinion

5(2- 7x)

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= 10-35x

8 0
3 years ago
B)When ABCD is drawn to scale, would
never [62]

Hi there there's several ways this could be proven one way us to consider the allied angle theory where two angles formed between parallel lines are supplementary which in this case can be proven by

2(45)+90=180⁰ ✔

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this would not be the case if it wasn't parallel

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7 0
2 years ago
In 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alc
Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol​ has changed.

Step-by-step explanation:

We are given that in 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alcoholic​ beverages?"

Of the 1100 adults​ surveyed, 429 indicated that they were total abstainers. In a recent​ survey, the same question was asked of 1100 adults and 352 in

<u><em>Let p = proportion of adults who totally abstain from alcohol.</em></u>

where, p = \frac{429}{1100} = 0.39

So, Null Hypothesis, H_0 : p = 39%      {means that the proportion of adults who totally abstain from alcohol​ has not changed}

Alternate Hypothesis, H_A : p \neq 39%      {means that the proportion of adults who totally abstain from alcohol​ has changed}

The test statistics that would be used here <u>One-sample z proportion statistics</u>;

                    T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who totally abstain from alcohol = \frac{352}{1100} = 0.32

           n = sample of adults surveyed = 1100

So, <u><em>test statistics</em></u>  =  \frac{0.32-0.39}{\sqrt{\frac{0.32(1-0.32)}{1100} } }  

                              =  -4.976

The value of z test statistics is -4.976.

<em>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</em><em> </em>

<em>Since our test statistics doesn't lie within the range of  critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the proportion of adults who totally abstain from alcohol​ has changed.

4 0
3 years ago
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