To answer, allow the width of the frame to be represented by x. The dimensions of the frame should then be, 11+2x and 6+2x. Subtracting the area of the inside of the frame from the area of the outside should be able to give us 18 cm². The equation,
(11 + 2x)(6 + 2x) - (11)(6) = 18
The value of x from the equation is equal to 0.5. Thus, the width of the frame should be 0.5 cm.
This is the concept of algebra, let the width be x
height=x-4
length=2x+10
the volume of the box is:
volume=length*width*height
=x(x-4)(2x+10)
expanding the above we get:
(x^2-4x)(2x+10)
=x^2(2x+10)-4x(2x+10)
=2x^3+2x^2-40x=264
solving the above we get real solution will be
x=6
thus we conclude that the width is x=6 inches
length=2*6+10=22 inches
height=x-4=6-4=2 inches
thus the dimension will be:
width=6 inches, length=22 inches, height=2 inches
Answer:
x=70
Step-by-step explanation:
9514 1404 393
Answer:
x = 21
y = 25
Step-by-step explanation:
The diagonals of a quadrilateral bisect each other, so each half of a diagonal is congruent to the other half.
x -2 = 19
x = 21 . . . . add 2
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y +1 = 26
y = 25 . . . . subtract 1
Answer:
Let that rational number to be subtracted be x.Given,-5/6 - x = 4/9= - x = 4/9+5/6= - x = 23/18x = - 23/18.
Step-by-step explanation:
