Question

A surveyor is conducting measures to see how wide a road is

Answer 1

Answer:

D) 45 ft

Step-by-step explanation:

The two triangles are shown below.

Given:

BC = 60 ft, CD = 24 ft and DE = 18 ft.

Since, the two triangles are similar, their corresponding sides are in proportion.

So, $\frac{AB}{DE}=\frac{BC}{CD}=\frac{AC}{CE}$

Now, consider the proportion of sides,

$\frac{AB}{DE}=\frac{BC}{CD}\\AB=\frac{BC}{CD}\times DE\\AB=\frac{60}{24}\times 18\\AB=\frac{60\times 18}{24}=45\ ft$

Therefore, the distance between A and B is 45 ft.