Question

The area of a rectangle is 108in2. The ratio of the length to the width is 4:3. Find the length and the width.

Answer 1

Let x be the length and y be the width.
Then we deduce the equations :
$xy=108\\ \frac{x}{y} = \frac{4}{3}$
From the first equation we get:
$x = \frac{4}{3} y$
Use the value of y in the first equation like this:
$(\frac{4}{3} y)y=108$
Solving the above equation for y we get:
$y=9$ then $x=12$