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Bond [772]
3 years ago
5

if the manufacturer makes 1500 beanbag chairs per day, how many of those chairs would they expect to be understuffed?​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

hiii

Step-by-step explanation:

may we chat in the comments sectiom

You might be interested in
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
Can I get help please! I need it right NOW
Luda [366]
6/7 because it’s a smaller fraction with more pieces. Brainliest???
5 0
3 years ago
If you answer this I will mark you brainliest
Temka [501]

Answer:

Here is the ans..hope it helps:)

8 0
2 years ago
How do you solve 4836÷12
ANEK [815]
The answer is 403, just try simple long division.
8 0
3 years ago
Read 2 more answers
7 + 2y = 8x 3x - 2y = 0 Solve the system of equations by substitution. (70/3, 140/9) (7/5, 21/10) no solution coincident
Wittaler [7]
So we have the system of equations:
7+2y=8x equation (1)
3x-2y=0 equation (2)

To use substitution, we are going to solve for one variable in one of our equations, and then we are going to replace that value in the other equation:
Solving for x in equation (2):
3x-2y=0
3x=2y
x= \frac{2}{3}y equation (3)

Replacing equation (3) in equation (1):
7+2y=8x
7+2y=8( \frac{2}{3} y)
7+2y= \frac{16}{3} y
7= \frac{10}{3} y
y= \frac{7}{ \frac{10}{3} }
y= \frac{21}{10} equation (4)

Replacing equation (4) in equation (3):
x= \frac{2}{3}y
x=( \frac{2}{3} )( \frac{21}{10} )
x= \frac{7}{5}

We can conclude that the solution of our system of equations is <span>(7/5, 21/10)</span>
5 0
3 years ago
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