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forsale [732]
3 years ago
6

Solve 3x^2 + 6x+15=0

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, x =  \frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}

Or, x = \frac{\sqrt{-144} }{6}

∴   x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )  Answer

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