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Strike441 [17]
3 years ago
11

The weight of a person on or above the surface of the earth varies inversely as the square of the distance the person is from th

e center of the earth. If a person weighs 180 pounds on the surface of the earth and the radius of the earth is 3900 miles, what will the person weigh if he or she is 325 miles above the earth's surface?
Mathematics
1 answer:
jeyben [28]3 years ago
8 0
Weight = k/(distance)². Let's find the value of k when distance = earth radius:

180 = k/(3900)² → k = 180 x 3900² → k = 2,737,800,000

If he is at 325 miles ABOVE the earth, the distance becomes: 3,900+325=4,225 miles and his weight becomes:

Weight = k/(distance)² → Weight = 2,737,800,000/(4225)² = 153.37

Weight = 153.37 lb

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2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
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3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.

-----

Answer: HJ = 25, JK = 25, HK = 50
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