Answer:
yes
Step-by-step explanation:
yes I want ☺️☺️☺️☺️☺️☺️
Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Fron the table given:
A3 = 112,
A8 = - 3,584
An = A1 *r ^ (n-1)
=> A3 = A1 (r^2) = 112
A8 = A1(r^7) = - 3,584
=> - 3584 / 112 = (r^7) / (r^2)
=> (r^5) = - 32
=> r = - 2
=> A1 (- 2)^2 = 112
=> A1 = 112 / 4 = 28
Answer: a1 = 28
It would have to be an obtuse triangle
B. 250 cm3 hope this helps
