Answer:
The possible dimensions of the deck can be anything that adds up to be 130 m.
Step-by-step explanation:
<em>The perimeter could be 1m x 64m.</em>
Two sides would be 1m each (so 2m total) and the other two sides would be 64m each (128m total). 2 + 128 = 130m.
<em>The perimeter could be 15m x 50m.</em>
Two sides would be 15m each (so 30m total) and the other two sides would be 50m each (100m total). 30 + 100 = 130m.
Answer:
A quadrant 1
Step-by-step explanation:
hope it helps
A x = 0
using the law of exponents 
= 1
for (6² )^ x = 1 then x = 0
B note that 
= 1 ⇒ x = 1
2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)
= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)
= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)
