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Marta_Voda [28]
3 years ago
8

A=1/2h (B+b) solve for h A=20 B=2 b=3

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
The h is 8. The answer is true!
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hodyreva [135]

Answer:

B. 14 square feet

Step-by-step explanation:

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7 0
3 years ago
A cylinder has a total volume of 678.59 and a height of 6m. what is the diameter of the cylinder? please help and show work
RoseWind [281]
Volume =
\pi {r}^{2} h
r = \sqrt{678.59 \div 6}
multiply r by 2 and you will get diameter
7 0
3 years ago
What is the area, in square units, of the trapezoid?
Misha Larkins [42]

Answer:

99

Step-by-step explanation:

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6 0
3 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
5(2z-2)=9(z+2) how to solve it
IceJOKER [234]

Answer:

z=28

Step-by-step explanation:

10z-10=9z+18

-9z        -9z

z-10=18

+10   +10

z=28

7 0
3 years ago
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