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Schach [20]
3 years ago
9

Let A and B are n x n matrices from which A is invertible. Suppose AB is singular. What conclusion can be made about the inverti

bility of B?
Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer: Matrix B is non- invertible.

Step-by-step explanation:

A matrix is said to be be singular is its determinant is zero,

We know that if a matrix is singular then it is not invertible.    (1)

Or if a matrix is invertible then it should be non-singular matrix.      (2)

Given :  A and B are n x n matrices from which A is invertible.

Then A must be non-singular matrix.                            ( from 2 )

If AB is singular.

Then either A is singular or B is singular but A is a non-singular matrix.

Then , matrix B should be a singular matrix.                   ( from 2 )

So Matrix B is non- invertible.                                     ( from 1 )

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