Answer: M=-2 , B= 2 , Equation: Y= -2x+2
Step-by-step explanation:
M is the slope. Slope is "rise / run", so 2 over -1. simplified, that is -2. B is the y-intercept, or where the graph crosses the y-axis. So, b will be 2.
Let n = required random sample size.
Assume that the population standard deviation is known as σ.
Let m = sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.
Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
(1.96σ)/√n = 0.03
√n = (1.96σ)/0.03
n = 128.05σ²
This means that the sample size is about 128 times the population variance.
Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.
Answer:

Step-by-step explanation:
First, you make fourteen a fraction.

Then, make it a mixed fraction by adding a six.

Lastly, have a great day! :)
Answer:
Step-by-step explanation:
5).
= 
= 
6). 
= x²
7). 
8). 
= 
9). 
10).
= 
= x³
EXPLANATION
The consecutive even numbers are

EXPLANATION
Let

be the first even number then, the next even number will be,

The difference of one-half the larger one and two-fifth the smaller one is 38 gives the equation,

We multiply through with an LCM of 10 to get,

This simplifies to,

We expand the brackets to get,

We group like terms to get,

This simplifies to

Therefore the next even number is is