Answer:
39 inches.
858 inches²
Step-by-step explanation:
Length:- (if length = x)
2 ( 11 + x ) = 100
22 + 2x = 100
2x = 100 - 22
2x = 78
x = 78 ÷ 2
x = 39 inches
Area:-
Area = l × b
= 39 × 22
= 858 inches²
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
x = -0.17 and x = -5.83
Step-by-step explanation:
We are asked to solve the quadratic equation
We use the quadratic formula using a = 1, b = 6 and c = 1
for a general quadratic equation of the form: 
Then, the solutions are given by;
which produces the two following answers (rounded to two decimals):
x = -0.17 and x = -5.83
Answer:12
Step-by-step explanation:
Answer:
It would be any positive slope.
