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Usimov [2.4K]
3 years ago
6

A cylinder has a volume of 24 cubic inches. What is the volume of a cone that the cone fits exactly inside of?

Mathematics
2 answers:
Karolina [17]3 years ago
5 0
Volume of cylinder = 24
volume of a cone = 1/3(volume of cylinder) = 1/3 (24) = 8

answer
8 <span>cubic inches</span>
zmey [24]3 years ago
5 0

Answer:

volume of cone is 8 cubic inches.

Step-by-step explanation:

We have been given that volume of cylinder = 24 cubic inches.

Since, cone fits exactly inside of the cylinder hence, we have

Volume of cylinder = volume of cone

Now, we know the formula

Volume of cone = \frac{1}{3}\pi r^2h

Volume of cylinder = \pi r^2h

Now, we have been given that

\pi r^2h=24

Therefore, we have

Volume of cone is given by

\frac{1}{3}\times24\\\\=8

Hence, volume of cone is 8 cubic inches.

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hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

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6 0
1 year ago
Find the arc length of the semicircle?
myrzilka [38]

Answer:

The length of the semicircle arc is 6π

Step-by-step explanation:

To solve this problem we need to use the circumferenc formula of a circle:

c = circumference

r = radius = 12

π = pi

c = π * d

we replace with the known values

c = π * 12

c = 12π

The length of the circumference is 12π

N ow we divide the circumference by 2 and we will obtain the length of the arc of the semicircle

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The length of the semicircle arc is 6π

6 0
3 years ago
Help me on my review quiz. 10 point btw
arsen [322]

Answer:

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6 0
3 years ago
Determine the slope between the points (-3, 0) and (0, 5)
Alex787 [66]
The slope is approximately 1.7x+5
5 0
4 years ago
Read 2 more answers
A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590
Jet001 [13]

Let's assume

height of plane  in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

y-y_1=m(x-x_1)

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{5900-6500}{7-5}

m=-300

Equation of line:

we can use formula

y-y_1=m(x-x_1)

we can plug values

h-6500=-300(t-5)

h=-300t+8000

Time of landing:

we can set h=0

and then we can solve for t

h=-300t+8000=0

t=\frac{80}{3}min..............Answer

5 0
4 years ago
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