<span>Given, y^2 - 14y = -44
Add 44 to both sides of the equation
</span>y^2 - 14y + 44 = -44 + 44<span>
</span>y^2 - 14y + 44 = 0
Using the quadratic formula x = [-b ± √(b² - 4ac)]/2a
Where,
a = 1
b = -14
c = 44
x = [-b ± √(b² - 4ac)]/2a
x = [-(-14) ± √(-14² - 4(1)(44)]/2(1)
x = [14 ± √(196 - 176)]/2
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 4.472)/2 OR (14 - 4.472)/2
x = 18.472/2 OR 9.528/2
x = 9.236 OR 4.764
The solution set is {9.236, 4.764}
TO EXPRESS THE ANSWER IN RADICALS
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 2√5)/2 OR (14 - 2√5)/2
<span>x = 7+√5 OR 7-√5
</span>
The solution set is {7+√5, 7-√5}
Answer:
3 ≤11 ≤ 11
Step-by-step explanation:
3x-4 = 2x +1
3x-5 = 2x
x-5 = 0
x= 5
3 ≤11 ≤ 11
Answer:91
Step-by-step explanation:
If the best grade is 100,91 is it.
The mean is 27.5. I hope this helps :)
There is an indeterminate form: infinity/infinity. To solve it, you can use the infinite comparison method. First, you have to identify which has the highest degree term: whether the numerator or the denominator. In this case, it is the numerator, which has the negative term of degree 4: -7x ^ 4. Then, the result is -∞.
Therefore, the answer is the last option: Does not exist.
