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Triss [41]
2 years ago
6

Hello :) so I'm horrible at math, but since finals are coming up I want to calculate what my final grade will be if I were to fa

il a chem test worth 50 points. Right now my grade is an A- (93.32%). Also what grade would I have to get on the final in order to keep an A- (at least 90%)?
Mathematics
2 answers:
Nutka1998 [239]2 years ago
7 0

Answer:

It depends on your total points and how much you already have

Step-by-step explanation:

So you gotta add up your total possible points right now and add 50 to it.

Then divide your current amount of points by the total possible points + 50.

Example. Suppose you had 93 points out of 100 right now.

Then you add 50 to 100 and you get 150.

After you divide 93 by 150, which equals 0.62.

Also, depends on whether exams and homework are weighted differently in your grading system.

Natalka [10]2 years ago
6 0

Answer:91

Step-by-step explanation:

If the best grade is 100,91 is it.

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Read 2 more answers
X²+Y²=250 and XY=117<br> What are the values of X and Y?
yan [13]

Answer:

<h3>            x = -9,  y = -13 </h3><h3>    or    x = 13,   y = 9</h3><h3>    or    x = -13,  y = -9</h3><h3>    or     x = 9,   y = 13</h3>

Step-by-step explanation:

x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad  x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}

y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9

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3 years ago
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