Compare the values of the underline 6,300 and 530

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

The value of 3 in 6,300 is 10 times the value of 3 in 530. And your welcome.

natka813 [3]3 years ago

4 0

Answer:

The value of 3 in 6,300 is 10 times the value of 3 in 530.

Step-by-step explanation:

Given :6,300 and 530

To find : Compare the values of the underline digits.

Solution : We have given 6,300 and 530

In 6,300

Value of 3 in 6,300 is 3 hundred = 300.

Value of 3 in 530 is 3 tens = 30.

3 hundred is 10 times of thirty

So, The value of 3 in 6,300 is 10 times the value of 3 in 530.

Therefore, The value of 3 in 6,300 is 10 times the value of 3 in 530.

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222+203 is rounded up to what?

miskamm [114]

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$1-5$ would rounded $downward$
$6-9$ would be rounded $upward$

3 0

3 years ago

Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line −3x+5y=−15? Drag and drop each choice in

nexus9112 [7]

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