Compare the values of the underline 6,300 and 530

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

The value of 3 in 6,300 is 10 times the value of 3 in 530. And your welcome.

natka813 [3]3 years ago

4 0

Answer:

The value of 3 in 6,300 is 10 times the value of 3 in 530.

Step-by-step explanation:

Given :6,300 and 530

To find : Compare the values of the underline digits.

Solution : We have given 6,300 and 530

In 6,300

Value of 3 in 6,300 is 3 hundred = 300.

Value of 3 in 530 is 3 tens = 30.

3 hundred is 10 times of thirty

So, The value of 3 in 6,300 is 10 times the value of 3 in 530.

Therefore, The value of 3 in 6,300 is 10 times the value of 3 in 530.

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Solve for x & y. 30x−42y=−6 and 5x−7y=−1

vladimir1956 [14]

Um.. Both of those equations are the exact same. Divide both sides of the first equation by 6. You get:

$\frac{30x - 42y}{6} = \frac{-6}{6} \\ 5x - 7y = -1$

That is the exact same as the second equation. This system has an infinite number of solutions. 5x - 7y = -1 is a line, so basically every point on that line is a solution to the system.

For example, $x = 0$ and $y = \frac{1}{7}$ would work, but so would $x = 1$ and $y = \frac{6}{7}$