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chubhunter [2.5K]
3 years ago
15

Compare the values of the underline 6,300 and 530

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0
The value of 3 in 6,300 is 10 times the value of 3 in 530. And your welcome.
natka813 [3]3 years ago
4 0

Answer:

The value of 3 in 6,300 is 10 times the value of 3 in 530.

Step-by-step explanation:

Given  :6,300 and 530

To find : Compare the values of the underline digits.

Solution : We have given 6,300 and 530

In 6,300

Value of 3 in 6,300 is 3 hundred = 300.

Value of 3 in 530 is 3 tens = 30.

3 hundred is 10 times of thirty

So, The value of 3 in 6,300 is 10 times the value of 3 in 530.

Therefore,  The value of 3 in 6,300 is 10 times the value of 3 in 530.

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Answer: perimeter = 96mm, Area = 564mm².

Step-by-step explanation:

From the diagram, it is a trapezium, it has a rectangle joined together by a right angled triangle. Now to find the perimeter, we add all the dimensions together. To get the other side of the rectangle, which is also the perpendicular height of the figure, we take the Pythagoras. Let the perpendicular height = x

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2

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