A ball is thrown from the top row of seats in a stadium. The function h(t) = - 16t^2 + 80t + 96 gives the height, in feet, of th
e ball t seconds after it is thrown. How long will it be before the ball hits the ground?
1 answer:
Answer:
2s or 3s
Step-by-step explanation:
Given the function that models the height of the object as;
h(t) = - 16t^2 + 80t + 96
The ball reaches the ground when h = 0
Substitute
0 = - 16t^2 + 80t + 96
Divide through by -16
0 = t²-5t-6
t²-5t-6 = 0
t²-2t-3t+6 = 0
t(t-2)-3(t-2) = 0
(tt-2)(t-3) = 0
t - 2 = 0 and t-3 = 0
t = 2 and 3s
Hence it will take the ball 2s or 3s to reach the ground
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Answer:
b)
Step-by-step explanation:
n²+n-42=0
Using mid-term break
n²+7n-6n-42=0
n(n+7)-6(n+7)=0
(n-6)(n+7)=0
Either,
n-6=0 OR n+7=0
n=6 OR n= -7
Combine like terms
2a² + 6a² = 8a²
8a² - 5
Hence, the distance between (7,8) and (-8,0) is:17
explanation: (a,b)=(7,8) and (c,d)=(-8,0)
Answer:
7/4 which could also be written as 1 and 3/4
just plug the numbers on the graph like (2,50)
