Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
126, 945 rounded to the nearest thousand is 127,000.
Answer:
y = - 4
Step-by-step explanation:
Given
y = 2x + ( - 2) , that is
y = 2x - 2 ← substitute x = - 1
y = 2(- 1) - 2 = - 2 - 2 = - 4
This is confirmed by the point (- 1, - 4 ) on the graph
Answer:
its just 9
Step-by-step explanation:
Divide: 3 : 1 / 3 = 3 / 1 · 3 / 1 = 3 · 3 / 1 · 1 = 9 / 1 = 9 Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator,
