Let's plug in a few points to see which graph belongs to the function f(x) = 2x^2

Let's say x =0, let's find y!
2(0)^2 = 2(0) = 0

So one point on our line is (0.0)

Just finding this point right here eliminates 3 of the answer choices. Your answer is the graph that goes through the point (0,0)

For your added convenience, I have attached the graph. :)

5 0

3 years ago

Here's a graph of a linear function. Write the

bazaltina [42]

Answer:

Step-by-step explanation:

The formula is y = mx + b

m being the slope, rise over run. And b being the y-intercept. Right off the bat we can visually see the y-intercept is -4.

To find slope, we need to take two sets of coords and apply the slope fomula. The slope fomula is change in y divided by the change in x. The function itself is straight, so that means the slope will be the exact same no matter which points you choose.

(4, -1) and (8, 2) are coords on the line. Do 2 - (-1) to get 3. then do 8 - 4 to get 4. Finally, we just gotta do 3/4 which is simply $\frac{3}{4}$ .

We have the slope of 3/4 and we have the y-intercept of -4. Just plug it in the standard formula of y = mx + b to get:

$y=\frac{3}{4} x-4$

5 0

3 years ago