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masya89 [10]
4 years ago
5

The graph shows the altitude of a helicopter over time.

Mathematics
1 answer:
NARA [144]4 years ago
8 0
The slope is 4000/15 = 266.67

the the slope shows how far the helicopter went total
i hope this helps
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How many four-character passwords can be formed using the characters A, B, C, 1, 2 if the characters can be repeated
olga55 [171]
<h3>Answer: 625</h3>

Work Shown:

The set {A,B,C,1,2} has five items. There are four slots to fill.

So we have 5^4 = 5*5*5*5 = 625 different possible passwords where the characters can be repeated.

7 0
3 years ago
A textile manufacturer wants to set up a control chart for irregularities (eg. oil stains, shop soil, loose threads, and tears)
Nookie1986 [14]

Answer:

UCLc = 25.7715519

LCLc =-4.171551971

find attached the C-chart(control chart)

Step-by-step explanation:

Sample Irregularities Sample Irregularity Sample Irregularity

1 18 6 11 11 10

2 14 7 4 12 16

3 6 8 10 13 5

4 14 9 12 14 15

5 8 10 9 15 17

Samples/Irre Cont'd

16 - 4

17 - 15

18 - 9

19 - 15

20 - 17

Using these? data, set up a? c-chart with z =33.

UCLc =

LCLc =

     Sample irreg     mean(CL) UCL LCL

              ularities

1 18 10.8 25.77155197 -4.171551971

2 14 10.8 25.77155197 -4.171551971

3 6 10.8 25.77155197 -4.171551971

4 14 10.8 25.77155197 -4.171551971

5 8 10.8 25.77155197 -4.171551971

6 11 10.8 25.77155197 -4.171551971

7 4 10.8 25.77155197 -4.171551971

8 10 10.8 25.77155197 -4.171551971

9 12 10.8 25.77155197 -4.171551971

10 9 10.8 25.77155197 -4.171551971

11 11 10.8 25.77155197 -4.171551971

12 16 10.8 25.77155197 -4.171551971

13 5 10.8 25.77155197 -4.171551971

14 1 10.8 25.77155197 -4.171551971

15 17 10.8 25.77155197 -4.171551971

16 4 10.8 25.77155197 -4.171551971

17 15 10.8 25.77155197 -4.171551971

18 9 10.8 25.77155197 -4.171551971

19 15 10.8 25.77155197 -4.171551971

20 17 10.8 25.77155197 -4.171551971

find attached the C-chart

Download xlsx
5 0
3 years ago
What is the value of y in the equation 5x+2y=20, when x=0.3
Rasek [7]

5x+2y=20

Substitute 0.3 for x

5(0.3)+2y=20

Multiply 5 by 0.3

1.5+2y=20

Subtract 1.5 from both sides

2y=18.5

Divide 2 on both sides

Final Answer: y= 9.25

8 0
4 years ago
What is  5.63×10−6in decimal form?a. 0.00000563 b. 0.000000563 c.5,630,000d. 56,300,000
Lelu [443]

5.63 \times  {10}^{ - 6}

To convert into decimal, move the decimal to the left by 6 positions.

It will be 0.00000563

Answer is A.
3 0
3 years ago
Chase consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Chase's body
PIT_PIT [208]

Answer:

(a) The 5-hour decay factor is 0.5042.

(b) The 1-hour decay factor is 0.8720.

(c) The amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

Step-by-step explanation:

The amount of caffeine in Chase's body decreases exponentially.

The 10-hour decay factor for the number of mg of caffeine is 0.2542.

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

(a)

Compute the 5-hour decay factor as follows:

5-hour\ decay\ factor=(0.8720)^{5}\\=0.504176\\\approx0.5042

Thus, the 5-hour decay factor is 0.5042.

(b)

The 1-hour decay factor is:

1-hour\ decay\ factor=(0.2542)^{1/10}=0.8720

Thus, the 1-hour decay factor is 0.8720.

(c)

The equation to compute the amount of caffeine in Chase's body is:

A = Initial amount × (0.8720)<em>ⁿ</em>

It is provided that initially Chase had 171 mg of caffeine, 1.39 hours after consuming the drink.

Compute the amount of caffeine in Chase's body 2.39 hours after consuming the drink as follows:

A = Initial\ amount \times (0.8720)^{2.39} \\=[Initial\ amount \times (0.8720)^{1.39}] \times(0.8720)\\=171\times 0.8720\\=149.112

Thus, the amount of caffeine in Chase's body 2.39 hours after consuming the drink is 149.112 mg.

4 0
3 years ago
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