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4 years ago

Find the area of the shape shown below.

Mathematics

2 answers:

Reil [10]4 years ago

6 0

Answer:

44.5

Step-by-step explanation:

(1 x 12) + (5 x 13)/2 = 44.5

polet [3.4K]4 years ago

6 0

Answer: 44,5 cm2

Step-by-step explanation:

Rektangel:

1 × 12 = 12 cm2

triangel:

13 × 5 = 65 cm2

78 ÷ 2 = 32,5 cm2

Area:

32,5 + 12 = 44,5 cm2

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Which equation represents a line perpendicular to the line shown on the graph y=1/2x-2

Marianna [84]

Answer:

y = -2x - 2

Step-by-step explanation:

The perp line is simply taking the negative reciprocal of the slope.

In this cale if +1/2 is the slope of the line, the flip it to get 2/1 which is just 2. Then multiply it by a negative.

4 0

3 years ago

Read 2 more answers

(1 pt)

BartSMP [9]

Since you are rounding to the nearest whole number, look at the digit in the tenth place. If it is 5 and greater, round up, if it is 4 and lower, round down

25.311 = 25
4.65 = 5

25 x 5 = 125

125 is your answer

hope this helps

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4 years ago

Read 2 more answers

Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=

LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio $1: \sqrt{3}:2$ . Remember the smallest side is always opposite the smallest angle, etc. These make a right triangle because

$1^2 + \sqrt{3}^2 = 2^2$

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the $\sqrt{3}$ side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions. Really you should memorize the sine and cosine so you can get these quickly.

$\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}$

$\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}$

$\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}$

$\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}$

$\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}$

$\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2$

We want the cotangent, another way to get it is

$\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}$

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3 years ago

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Mark and Bonnie both make $11 per hour working for their parents. If they combine their efforts and work for the same amount of

Mademuasel [1]

To answer this we would need the expressions given.

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3 years ago

What is the distance between negative 2.25 and positive 2.75

VikaD [51]

Answer:

Step-by-step explanation: