Answer:
The option is C i.e 115°, 65°. proof is given below.
Step-by-step explanation:
Given:
ABCD is a quadrilateral.
m∠ A = 100 + 5x
m∠ B = 77 - 4y
m∠ C = 106 + 3x
m∠ D = 47 + 6y
To Prove:
ABCD is a parallelogram if opposing angles are congruent by finding the measures of angles.
m∠ A = m∠ C and
m∠ B = m∠ D
Proof:
ABCD is a quadrilateral and is a parallelogram if opposing angles are congruent.
∴ m∠ A = m∠ C
On substituting the given values we get
∴ 100 + 5x = 106 +3x
∴ 
m∠ A = 100 + 5x = 100 + 5 × 3 =100 + 15 = 115°
m∠ C = 106 + 3x = 106 + 3 ×3 =106 + 9 = 115°
∴ m∠ A = m∠ C = 115°
Similarly,
∴ m∠ B = m∠ D
77 - 4y = 47 + 6y
10y = 77 - 47
10y =30
∴
m∠ B = 77 - 4y =77 - 4 × 3 = 77 - 12 = 65°
m∠ D = 47 + 6y = 47 + 6 × 3 = 47 + 18 = 65°
∴ m∠ B = m∠ D = 65°
Therefore the option is C i.e 115°, 65°
The answers are: 4.5 g and 56.25 g respectively.
Since the first type of measurement in this question is weight or mass, I'll suppose that the percentage concentration is % mass/mass. For that type of concentration measurement, just multiply the percentage by the total mass to get the mass of the wanted material.
So 150 g * 3% = 150 g * 0.03 = 4.5g
For the 8% solution with the same amount of dry substance, use the ratio of percentages, multiplied by the mass of the first solution to get the wanted amount of new solution:
3/8 * 150 g = 56.35 g
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
2 petunias leave $6.50 on her wallet, and 8 leave $5.00. This means that 6 petunias cost $1.50, and that 1 petunia costs 25 cents.
.25 goes into 3.50 (the amount of money she has left in her wallet after buying 14 petunias) 14 times. 14 + 14 =28.
Ying Ying can buy 28 petunias at most.
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